A ray of light incident at a certain angle on a prism having a refract

1.	A ray of light incident at a certain angle on a prism having a refracting angle 53° suffers minimum deviation. If the angle of minimum deviation is 41°, what is the angle of incidence?pls ans asap dont spam!otherwise reported
Answer» Conditions for MINIMUM DEVIATION: angle of INCIDENCE(i) = angle of emergence(e) R1 = r2 = A/2 A = refracting angle. $\rm \delta_{min} = minimum \: deviation$ $\boxed{\bf \delta_{min} = 2i-A}$ Solution: $\implies\sf \delta_{min} = 2i-A$ $\implies\sf 41\degree = 2i-53\degree$ $\implies\sf 2i = 41\degree + 53\degree$ $\implies\sf i = \dfrac{94\degree}{2} = 47\degree$ ★ Angle of incidence is 47° ------------------------------------------