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A railroad car of mass M is at rest on frictionless rails when a man of mass m starts moving on the car towards the engine. If the car recoils with a speed v backward on the rails, with what velocity is the man approaching the engine? |
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Answer» THANKS for asking the question! ANSWER:: Let the mass moving with a velocity X with respect to the engine. Velocity of the mass with respect to earth is (x-v) towards right. Centre of mass of V = 0 (initially at REST) Therefore , 0 = -Mv + m(x-v) Mv = m(x-v) mx = Mv + mv x = [v(M+m)/m] x = [1 + M/m] v Hope it helps! |
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