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A radioactive sample at any instant has its disintegration rate `5000` disintegrations per minute After `5` minutes , the rate is `1250` disintegration per minute. Then , the decay constant (per minute)A. 0.8 ln 2B. 0.4 ln 2C. 0.2 ln 2D. 0.1 ln 2 |
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Answer» Correct Answer - B `lambda=("log"_e A_1/A_2)/t =("log"_(e) "5000"/"1250")/5` =0.4 In 2 |
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