1.

A radio set does 20 joules of work in 5 sec. What is its power? How many units of energy consumed if it is operated for 6 hours?

Answer» POWER =

\frac{work \: done}{time \: taken \: }
\frac{20 \: \: joules}{5 \: \: sec}
= > 4 \: watt

ENERGY CONSUMED FOR 6 HOURES

=>>>>
\frac{power \times time}{1000}

\frac{4 \times 6 \times 60 \times 60}{1000}
\frac{864}{10}

8.64JOULE


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