A quadrilateral has one of its diagonal 14.8cm the altitudes draw to t

1.	A quadrilateral has one of its diagonal 14.8cm the altitudes draw to this diagonal 8.4cm and 5.7 cm find its area
Answer» Given: One of the DIAGONAL of the quadrilateral = 14.8 cm Altitudes drawn to this diagonal are 8.4 cm and 5.7 cm. To find: The area of the quadrilateral Solution: We know that The area of a quadrilateral is half the PRODUCT of the length of one of its diagonal "d" and the SUM of the length of altitudes "h₁" & "h₂" drawn from opposite vertices to that diagonal. $\boxed{\boxed{\bold{Area = \frac{1}{2} \times d\times [h_1+ h_2] }}}$ Here d = 14.8 cm h₁ = 8.4 cm h₂ = 5.7 cm Therefore, substituting the VALUES in the formula, we get Area of the given quadrilateral is, = $\frac{1}{2} \times 14.8 \times [8.4\: + \:5.7]$ = $\frac{1}{2} \times 14.8 \times 14.1$ = $7.4 \times 14.1$ = $\bold{104.34\:cm^2}$ Thus, its area is 104.34 cm². ---------------------------------------------------------------------------------------------- Also View: Find the area of the quadrilateral brainly.in/question/8888173 Find the area of the quadrilateral brainly.in/question/3300684

A quadrilateral has one of its diagonal 14.8cm the altitudes draw to this diagonal 8.4cm and 5.7 cm find its area

Answer»

Given:

One of the DIAGONAL of the quadrilateral = 14.8 cm

Altitudes drawn to this diagonal are 8.4 cm and 5.7 cm.

To find:

The area of the quadrilateral

Solution:

We know that

The area of a quadrilateral is half the PRODUCT of the length of one of its diagonal "d" and the SUM of the length of altitudes "h₁" & "h₂" drawn from opposite vertices to that diagonal.

$\boxed{\boxed{\bold{Area = \frac{1}{2} \times d\times [h_1+ h_2] }}}$