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A pump can fill a pot in 2 hours, because of a leakage in the bottom of the pot, it will take \(2\frac{1}{3}\) hours to fill the pot. In what time can the leakage empty the pot?1. 8 hours2. 7 hours3. \(4\frac{1}{3}\) hours4. 14 hours |
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Answer» Correct Answer - Option 4 : 14 hours Given: A pump can fill a pot in 2 hours. With leakage, the pot can be filled in \(2\frac{1}{3}\) hours Concept: If a tap can fill a tank in x hours, then the tank filled by the tap in 1 hour = 1/x of the total tank. Calculation: Work done in 1 hour by the pump = 1/2 Work done in 1 hour by leakage and pump = 3/7 Work done by the leakage in 1 hour = (1/2) – (3/7) ⇒ (7 – 6)/14 ⇒ 1/14 ∴ The leakage can empty the pot in 14 hours. |
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