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A pulley is attached to one arm of a balance and a string passed around it carries two masses `m_(1)` and `m_(2)`. The pulley is provided with a clamp due to which `m_(1)` and `m_(2)` do not move. On removing the clamp, `m_(1)` and `m_(2)` start moving. How much change in counter mass has to be made to restore balance ? A. `g(m_(1)-m_(2))^(2)/((m_(1)+m_(2))` to be reducedB. `g(m_(1)-m_(2))^(2)/((m_(1)+m_(2))` to be increasedC. `g(m_(1)-m_(2))/((m_(1)+m_(2))`to be increasedD. `g(m_(1)-m_(2))/((m_(1)+m_(2))`to be increased |
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Answer» When `m_(1)` & `m_(2)` not moving Then `W_(1)= (m_(1)+m_(2))g` When `m_(1) & `m_(2)` are moving W_(2) `=(4m_(1)m_(2)g)/(m_(1)+m_(2))` `:.` Reduced wt`=W_(1)-W_(2)` |
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