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A pull of 15 N is applied on a rope attached to a block of mass 7 kg lying on a smooth horizontal surface. Exerted on the rope by the block ? |
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Answer» Solution :Here ` F_(1) = 15 N , ` ` m_(1) = 7 kg , m_(2) = 0.5 kg F = ` ? ACCELERATION produced , ` a = (F_(1))/(m_(1) + m_(2) )=(15 )/((7 +0 .5 ) )= 2 m//s^(2) ` Force exerted by rope on the black , ` F = m_(1) a = 7 xx 2 = 14 N ` As a REACTION , force exerted on the rope by the block = 14 N ` (##PR_XI_V01_C03_S01_062_S01##) ` . |
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