a proton with rest mass of 1.6 x10^-27 kg moving in accelerator with a

1.	a proton with rest mass of 1.6 x10^-27 kg moving in accelerator with a speed of 0.6c . its total energy is
Answer» ENERGY can be calculated using the mass-energy formula: $E=mc^2$ . However, we need to use the relativistic formula, because the speed is RELATIVE to that of LIGHT. Therefore, the formula is: $E = \alpha mc^2$ . Where $\alpha$ is the LORENTZ factor of the relativistic formula. $\alpha =\frac{1}{\sqrt{1-\frac{v^2}{c^2} } }$ . Here, the velocity is 0.6c. Therefore, $\alpha =\frac{1}{\sqrt{1-\frac{(0.6c)^2}{c^2} } }$ . $\alpha =\frac{1}{\sqrt{1-\frac{0.36c^2}{c^2} } }$ . $\alpha =\frac{1}{\sqrt{1-0.36} } \\\alpha =\frac{1}{\sqrt{0.64} } \\\alpha =1.25$ . Therefore, $E=1.251.610^{-27}(310^8)^2=1.876151435613099938*10^{-10}J$

a proton with rest mass of 1.6 x10^-27 kg moving in accelerator with a speed of 0.6c . its total energy is

Answer»

ENERGY can be calculated using the mass-energy formula: $E=mc^2$ .

However, we need to use the relativistic formula, because the speed is RELATIVE to that of LIGHT. Therefore, the formula is: $E = \alpha mc^2$ . Where $\alpha$ is the LORENTZ factor of the relativistic formula.