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A proton moving with a velocity 3* 10^5 enters a magnetic field of 0.3T at an angle of 30degree with the field. The radius of curvature of its path will be . a)3Q/2 b)Q/2 c)Q/4 d)Q |
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Answer» 3Q/2hope it MAY be you PLEASE MARK me as a BRAINLIEST please mark me and FOLLOW me |
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