A proton (mass m) accelerated by a potential difference V flies through a uniform transverse magnetic field B. The field occupies a region of space by width 'd'. If alpha ' be the angle of deviation of proton from initial direction of motion (see figure), the value of sin a will be:

A proton (mass m) accelerated by a potential difference V flies throug

1.	A proton (mass m) accelerated by a potential difference V flies through a uniform transverse magnetic field B. The field occupies a region of space by width 'd'. If alpha ' be the angle of deviation of proton from initial direction of motion (see figure), the value of sin a will be:
Answer» `qVsqrt( (pd )/(2m))` `BD sqrt((q)/( 2MV))` `(B)/(d )sqrt((q)/(2mV))` `(B )/(2)sqrt((qd)/(MV))` Answer :B

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A proton (mass m) accelerated by a potential difference V flies through a uniform transverse magnetic field B. The field occupies a region of space by width 'd'. If alpha ' be the angle of deviation of proton from initial direction of motion (see figure), the value of sin a will be:

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