1.

a proton carrying 1MeV kinetic energy is moving in a circular path or radius r in uniform magnetic field . what should be the energy of alpha particle to describe a circle of same radius in the field​

Answer»

ANSWER:

For a particle of mass m and charge Q in a magnetic FIELD, the radius of the path is given by;

R= \sqrt{x}2M(KE)/qB

q∝ \sqrt{x}m(KE)

2e/e=\sqrt{x}(mp)(IMeV)/(4m p)(KE)

1/4= 1/4(KE)

KE=1MeV



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