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a proton carrying 1MeV kinetic energy is moving in a circular path or radius r in uniform magnetic field . what should be the energy of alpha particle to describe a circle of same radius in the field |
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Answer» For a particle of mass m and charge Q in a magnetic FIELD, the radius of the path is given by;
q∝ 2e/e= 1/4= 1/4(KE) KE=1MeV |
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