A proton accelerated through a potential difference of 100V, has de-Broglie wavelength lamda_0 . The de-Broglie wavelength of an alpha-particle, accelerated through 800V is

A proton accelerated through a potential difference of 100V, has de-Br

1.	A proton accelerated through a potential difference of 100V, has de-Broglie wavelength lamda_0 . The de-Broglie wavelength of an alpha-particle, accelerated through 800V is
Answer» `(lamda_0)/(sqrt2)` `(lamda_0)/(2)` `(lamda_0)/(4)` `(lamda_0)/(8)` SOLUTION :`lamda_p/lamda_alpha = sqrt( (m_alpha q_alpha V_alpha)/(m_p q_p V_p) ) = sqrt(( (4m_p) (2e) XX (800) )/( (m_p) xx (e ) xx (100) ) ) = 8` `rArr lamda_alpha = (lamda_p)/(8) = (lamda_0)/(8)`

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A proton accelerated through a potential difference of 100V, has de-Broglie wavelength lamda_0 . The de-Broglie wavelength of an alpha-particle, accelerated through 800V is

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