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A proton accelerated by a potential difference 500 kV flies through a uniform transverse magnetic field with induction B=0.51 T. The field occupies a region of space d=10 cm thickness as in figure. Find the angle (in degree) through which the proton deviates from the initial direction of motion.Take charge of proton as 1.6×10−19C and mass of the proton is 1.6×10−27kg |
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Answer» A proton accelerated by a potential difference 500 kV flies through a uniform transverse magnetic field with induction B=0.51 T. The field occupies a region of space d=10 cm thickness as in figure. Find the angle (in degree) through which the proton deviates from the initial direction of motion. Take charge of proton as 1.6×10−19C and mass of the proton is 1.6×10−27kg  |
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