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a projector lamp can be used at a maximum voltage of 60v its resistance is 20ohm the series resistance required to operate lamp from 75v supply is |
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Answer» Final ANSWER: Minimum series Resistance : 5ohmSteps and Understanding:1) Maximum POTENTIAL difference across lamp is 60V.Internal Resistance of Lamp, r = 20ohm.Maximum CURRENT across it that will flow through out the. circuit,By Ohm, 's Law,I(max) = V(max) / r = 60/ 20 = 3A.2) SINCE, 60 V is across Lamp so remaining15 V will. be across External Resistor.Current, I(max) = 3A.Minimum Resistance, R = 15V/ 3 = 5ohm.This is resistance required to sufficient use of lamp at Max Volt 60 across lamp.hope it helps |
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