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A projective of 2kg was velocities 3m/s and 4m/s at two points its flight in the uniform gravitational field of the earth. If these two velocities are _|_ to each other than the minimum KE of the particle during its flightis |
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Answer» Solution :`V_(1)cosalpha = V_(2)cos(90-alpha)` `3cosalpha = 4sinalpha` `TAN alpha = (3)/(4) ` `KE_(min) = (1)/(2)mv_(1)^(2)cos^(2)alpha` `= (1)/(cancel2)xxcancel(2)xx3xx((4)/(5))^(2) = (9xx16)/(25) =` 5.76J |
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