A projectile is thrown with a velocity of 20 m/sat an angle of 60° wi

1.	A projectile is thrown with a velocity of 20 m/sat an angle of 60° with the horizontal. After howmuch time the velocity vector will make an angleof 45° with the horizontal: (take g 10 m/s?)(1) v3 sec(2) 1/3 sec3) (v3 + 1) sec (4) (3 -1) sec
Answer» For velocity to make 45° the vertical and horizontal velocity should be equal horizontal component of velocity is always constant as it is 20cos(60°) =10m/s and initial velocity in vertical direction = 20sin(60) = 10√3 so, for vertical component to change to 10m/s use V = u-gt => 10 = 10√3 -10t=> 10t = 10(√3-1)=> t = √3-1 sec option 4

A projectile is thrown with a velocity of 20 m/sat an angle of 60° with the horizontal. After howmuch time the velocity vector will make an angleof 45° with the horizontal: (take g 10 m/s?)(1) v3 sec(2) 1/3 sec3) (v3 + 1) sec (4) (3 -1) sec

Answer»

For velocity to make 45°

the vertical and horizontal velocity should be equal

horizontal component of velocity is always constant as it is 20cos(60°) =10m/s

and initial velocity in vertical direction = 20sin(60) = 10√3 so, for vertical component to change to 10m/s

use V = u-gt => 10 = 10√3 -10t=> 10t = 10(√3-1)=> t = √3-1 sec

option 4

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A projectile is thrown with a velocity of 20 m/sat an angle of 60° with the horizontal. After howmuch time the velocity vector will make an angleof 45° with the horizontal: (take g 10 m/s?)(1) v3 sec(2) 1/3 sec3) (v3 + 1) sec (4) (3 -1) sec

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