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A projectile is thrown upward with a velocity `v_(0)` at an angle `alpha` to the horizontal. The change in velocity of the projectile when it strikes the same horizontal plane isA. `v_(0) sin alpha` vertically downwardB. `2v_(0) sin alpha` vertically downwardC. `2v_(0) sin alpha` vertically upwardD. zero |
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Answer» Correct Answer - B `Deltav = a Deltat` (as a = constant) `= (-g hatj) ((2v_(0) sin alpha)/(g)) = (-2v_(0) sin alpha)hatj` i.e., change in velocity is `2v_(0) sin alpha`, vertically downwards. |
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