A projectile is projected at angle 45° with horizontal at speed 36 km

1.	A projectile is projected at angle 45° with horizontal at speed 36 km/hr. Find the time after which velocity becomes perpendicular to initial velocity.
Answer» EXPLANATION: V y =V X =U x =ucosα ⇒ucosα=usinα−gt gt=u(sinα−cosα) t= g u(sinα−cosα)

A projectile is projected at angle 45° with horizontal at speed 36 km/hr. Find the time after which velocity becomes perpendicular to initial velocity.

Answer»

EXPLANATION:

=ucosα

⇒ucosα=usinα−gt

gt=u(sinα−cosα)

u(sinα−cosα)

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A projectile is projected at angle 45° with horizontal at speed 36 km/hr. Find the time after which velocity becomes perpendicular to initial velocity. ​

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A projectile is projected at angle 45° with horizontal at speed 36 km/hr. Find the time after which velocity becomes perpendicular to initial velocity.