A projectile is given an initial velocity of (^i+2^j)m/s, where ^i is along the ground and ^j is along the vertical. If g=10m/s2 the equation of its trajectory is:

A projectile is given an initial velocity of (^i+2^j)m/s, where ^i is

1.	A projectile is given an initial velocity of (^i+2^j)m/s, where ^i is along the ground and ^j is along the vertical. If g=10m/s2 the equation of its trajectory is:
Answer» A projectile is given an initial velocity of $(^i + 2^j) m / s$ , where $^i$ is along the ground and $^j$ is along the vertical. If $g = 10 m / s^{2}$ the equation of its trajectory is:

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A projectile is given an initial velocity of (^i+2^j)m/s, where ^i is along the ground and ^j is along the vertical. If g=10m/s2 the equation of its trajectory is:

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