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| 1. |
A projectile is fired with initial velocity of 90m/s to hit a ground level target. its maximum horizontal range will be: |
| Answer» SINCE the (VERTICAL) velocity of the ball is GIVEN by (assuming g≈ constant)v(t)=dsdt=v0−gt,the speed of the object when HITS the GROUND is the velocity at time t∗, where t∗ is the value of t when s(t)=sG=0 (if your reference system is placed at s=sG=0 for | |