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A potentiometer wire of length `10m` and resistance `20Omega` is connected in series with another resistance of `80Omega` and a battery of emf `4V`. The potential gradient on the wire will be (in `mV//cm`)A. `0.8`B. `0.16`C. `0.2`D. `0.4` |
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Answer» Correct Answer - A `V_(1):V_(2)=R_(1):R_(2)=1:4impliesV_(1)=(1)/(5)(4)=0.8V` `:.` Potential gradient `=(0.8)/(10)Vm^(-1)=0.08Vm^(-1)` `=0.8mV cm^(-1)` |
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