Saved Bookmarks
| 1. |
A potential difference of `10^(3)` V is applied across an X-ray tube. The ratio of the de-Broglie wavelength of the incident electrons to the shortest wavelength of X-rays products is - `(e//m=1.8xx10^(14)C//kg`for an electron)A. `1//20`B. `1//100`C. 1D. None of these |
|
Answer» Correct Answer - C For incident electron `lambda_(1) =(h)/(p) =(h)/sqrt(2Km)=(h)/(sqrt(2m Ve))` and shortest wavelength of X- rays is `lambda_(2)=(hc)/(Ve)` `(lambda_(1))/(lambda_(2))=1/c sqrt(((V)/(2))((e)/(m)))` Substituting the value we get `(lambda_(1))/(lambda_(2)) =1` |
|