Saved Bookmarks
| 1. |
A potential barrier of 0.50 V exists across a p-n junction. An electron with a speed of 5.0 xx 10^5m/s approaches the p-n junction from the n-side. With what speed will it enter the p-side ? |
Answer» Solution : Suppose the electron has a speed `v_1 `, when it ENTERS the DEPLETION layer and `v_2`, when it comes out of it. As the potential energy increases by `e xx 0.50 `V, from the principle of CONSERVATION of energy. ` 1/2 m upsilon_(1)^(2)= e xx 0.50+ 1/2m upsilon_(2)^(2)` `1/2( 9.1 xx 10^(-31)) ( 5 xx 10^5 )^2 ` `= 1.6 xx 10^(-19) xx 0.5+1/2xx 9.1xx 10^(-31) xx upsilon_(2)^(2)` Solving this, ` upsilon _2 = 2.7 xx 10^5 m//s` |
|