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A position dependent force F=ysquare x icap +xsquare y jcap acts on a particle and displace it from x = 1 m, y = 2 m to x = 2 m, y = 1 m. The work done by the force isOptions: J10 J20 JShould have chosen Zero |
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Answer» A position dependent force F=ysquare x icap +xsquare y jcap acts on a particle and displace it from x = 1 m, y = 2 m to x = 2 m, y = 1 m. The work done by the force is Options: J 10 J 20 J Should have chosen Zero |
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