1.

A position dependent force F=ysquare x icap +xsquare y jcap acts on a particle and displace it from x = 1 m, y = 2 m to x = 2 m, y = 1 m. The work done by the force isOptions: J10 J20 JShould have chosen Zero

Answer» A position dependent force F=ysquare x icap +xsquare y jcap acts on a particle and displace it from x = 1 m, y = 2 m to x = 2 m, y = 1 m. The work done by the force is

Options:

J

10 J

20 J

Should have chosen
Zero


Discussion

No Comment Found

Related InterviewSolutions