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A polygon has 27 diagonals.What is the no. of sides of the polygon? |
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Answer» Answer: 9 Step-by-step EXPLANATION: The number of diagonals in a polygon = N(n-3)/2 = 27 n(n-3) = 54 n²-3n - 54 = 0 (n - 9)(n+6) = 0 n = 9 sides = 9 |
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