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A pole of height 4 m is kept in front of a vertical plane mirrorof length 2m. The lower end of the mirror is at a height of 6m form the grown .the horizontal distance betweem the mirror and the pole is 2m. Upto what minimum and maximum heights a man can see the image of top of the pole at a horizontal distance of 4m (from the mirror O standing on the same horizontal line which is passing through the pole and the horizontal point below the mirror? |
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Answer» Solution :`PQ="Pole", MN="Image of pole" ` `(HG)/(GN)=(BD)/(BN)` `:. BD=((HG)(BN))/(GN)=((2)(6))/(2)` `=6 M` Minimum height required `=AD=BD+AB=10m` Further ,`(IG)/(GN)=(BE)/(BN)` `:. BE=((IG)(BN))/(GN)=((4)(6))/(2)=12 m` `:.` MAXIMUM height required `=AE` `=BE+AB=16 m`. 
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