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A point source of light B is placed at a distance L in front of the center of a mirror of width 'd' hung vertically on a wall. A man walks in front of the mirror along aline parallel to the mirro at a distance 2L from it as shown in figure. The greatest distance over which he can see the image of the light source in the mirror is |
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Answer» `d//2` In `DELTA`ANM and `Delta`ADC, `angleADC=angleANM=90^(@)``[MN_|_AD]` `angleMAN=angleCAN` (law of REFLECTION) `=DeltaANM` is similar to `DeltaADC` `:. (x)/(2L)=(d//2)/(L) or x=d` So, required distance `=d+d+d=3d`. Therefore, (d) is the correct option. 
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