A point P is moving with uniform angular speed along a circle of radius R the speed of its projection Q on the diameter will be? A: V=ω√r^2 - x^2B: V= ω^2 (r-x)C: V=ω/r √r^2 - x^2D: V= 1/ω √r^2 - x^2

A point P is moving with uniform angular speed along a circle of radiu

1.	A point P is moving with uniform angular speed along a circle of radius R the speed of its projection Q on the diameter will be? A: V=ω√r^2 - x^2B: V= ω^2 (r-x)C: V=ω/r √r^2 - x^2D: V= 1/ω √r^2 - x^2
Answer» The particle has only CENTRIPETAL acceleration and no tangential acceleration since it is moving with a uniform SPEED ωr AROUND the circle .THEREFORE , acceleration of the particle = ω 2 r

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A point P is moving with uniform angular speed along a circle of radius R the speed of its projection Q on the diameter will be? A: V=ω√r^2 - x^2B: V= ω^2 (r-x)C: V=ω/r √r^2 - x^2D: V= 1/ω √r^2 - x^2 ​

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A point P is moving with uniform angular speed along a circle of radius R the speed of its projection Q on the diameter will be? A: V=ω√r^2 - x^2B: V= ω^2 (r-x)C: V=ω/r √r^2 - x^2D: V= 1/ω √r^2 - x^2