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A point object is placed in air at a distance ' \( R \) ' in front of a convex spherical refracting surface of radius of curvature \( R \). If the medium on the other side of the surface is glass, then the image is :(i) real and formed in glass.(ii) real and formed in air.(iii) virtual and formed in glass.(iv) virtual and formed in air. |
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Answer» Since object distance is R , curvature is R and we have an convex spherical surface in air (N2/v)-(N1/u)=(N2-N1)/R As ojbect is in air RI of air will be 1 and R will be negative due to sign convention N2/v-1/(-R)=N2-1/R N2/v = N2-1/R - 1/R As N2 is glass N2-1/R is smaller than 1/R and hence v is negative - making V virtual and in air as object is in air |
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