A point moves along an arc of a circle of radius R. Its velocity depends upon the distance covered `s' as v=A√s, where a is constant. The angle θ between the vector of total acceleration and tangential acceleration is:

A point moves along an arc of a circle of radius R. Its velocity depen

1.	A point moves along an arc of a circle of radius R. Its velocity depends upon the distance covered `s' as v=A√s, where a is constant. The angle θ between the vector of total acceleration and tangential acceleration is:
Answer» A point moves along an arc of a circle of radius R. Its velocity depends upon the distance covered `s' as $v = A \sqrt{s}$ , where a is constant. The angle $θ$ between the vector of total acceleration and tangential acceleration is:

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A point moves along an arc of a circle of radius R. Its velocity depends upon the distance covered `s' as v=A√s, where a is constant. The angle θ between the vector of total acceleration and tangential acceleration is:

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