1.

A point equidistant from the line 4x + 3y + 10 = 0, 5x − 12y + 26 = 0 and 7x+ 24y − 50 = 0 is(a) (1, −1)(b) (1, 1)(c) (0, 0)(d) (0, 1)

Answer» A point equidistant from the line 4x + 3y + 10 = 0, 5x − 12y + 26 = 0 and 7x+ 24y − 50 = 0 is



(a) (1, −1)

(b) (1, 1)

(c) (0, 0)

(d) (0, 1)


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