1.

A point charge Q is placed at point O as shown in the figure. The potential difference VA – VB is positive. Is the charge Q negative or positive?

Answer»

We know that, V = \(\cfrac{1}{4\pi\varepsilon_0}\cfrac{Q}r\)

⇒ V \(\propto\cfrac1r\)

The potential due to a point charge decreases with increase of distance.

VA – VB > 0 ⇒ VA > VB

Hence, the charge Q is positive.



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