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A player catches a ball of 200 g moving with a speed of 20 m/s if the time taken to complete the catch is 0.5 s , the force exerted on the player's hand is (a) 8 n(b) 4 n(c) 2 n(d) 0 ​

Answer» GIVEN mass = 200ginitial velocity = 20m/sfinal velocity = 0 m/stime =0.5Change in momentum = 0.2 × 20 = 4kgForce = 4/0.5 = 8 NMark my answer as a Brainliest.


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