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A plane wall is 20 cm thick with an area of 1 m2 and has a thermal conductivity of 0.5 W/m. K. A temperature difference of 100°C is imposed across it. The heat flow is at : (a) 150 W (b) 180 W(c) 220 W (d) 250 W |
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Answer» (d) 250 W K = 0.5 W/m A = 1 m2 t = 20 cm = 20 × 10–2 m = 0.2 \(\Delta\theta\) = 100°C So, Q = \(\cfrac{KA\Delta\theta}t\) = \(\cfrac{0.5\times1\times100}{0.2}\) = 250 W |
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