1.

A plane wall is 20 cm thick with an area of 1 m2 and has a thermal conductivity of 0.5 W/m. K. A temperature difference of 100°C is imposed across it. The heat flow is at : (a) 150 W (b) 180 W(c) 220 W (d) 250 W

Answer»

(d) 250 W

K = 0.5 W/m 

A = 1 m2 

t = 20 cm = 20 × 10–2 m = 0.2 

\(\Delta\theta\) = 100°C

So, Q = \(\cfrac{KA\Delta\theta}t\)

\(\cfrac{0.5\times1\times100}{0.2}\) = 250 W



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