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A piece of work is complete by A in 20 days, the same is complete in 10 days by B. in how many days that work can be complete by both of them. |
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Answer» Work done by A in 5 days = 1/20*5 =1/4remaining work=(1-1/4) =3/4now,3/4 work is done by B in 10 dayswhole work will be done by B in 10*4/3= 40/3 daysas 1 day's work of A = 1/201 day's work of B =3/40(A+B)'s 1 day's work= 1/20+3/40 = 1/8so,both finished the work in 8 day's. |
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