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A piece of wood from an archaeological source shows a `.^(14)C` activity which is `60%` of the activity found in fresh wood today. Calculate the age of the archaeological sample. (`t_(1//2)` for `.^(14)C = 5570` year) |
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Answer» Correct Answer - 4252 years `((a)/(a-x))=(N_(0))/(N)=(100)/(60)` `K=(0.693)/(t_(1//2))=(0.693)/(57770)` `:.t=(2.303)/(K)log((N_(0))/(N))` `=(2.303xx5770year)/(0.693)log((100)/(60))` `:.t=(2.303)/(K)log((N_(0))/(N))` `=(2.303xx5770year)//(0.693)(2-1.7781)` `=4252 years` |
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