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A piece of wire of resistance 10 ohm is drawn out so that its length is increased to three times its original length. Calculate the new resistance. |
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Answer» Resistance R = 10 Ω Let l be the length of the wire R ∝ 1 When the length is increased to three times, l’ = 3l ∴ New Resistance R’ ∝ l’ ∝ 3l ∴ \(\frac{R}{R'} = \frac{l}{3l} = \frac{1}{3}\) ∴ R' = 3R New resistance = 3 times the original resistance. |
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