1.

A piece of wire is bent in the shape of equilateral triangle each of whose sides measure 8.8 cm. This wire is rebent to form a circle. What is the diameter of the circle.

Answer»

Answer:

Diameter of circle will be - 8.4 cm

Step-by-step explanation:

Given   SIDE of equilateral triangle = 8.8 cm

             So the perimeter of triangle will be     3 x 8.8 = 26.4 cm

Now this triangle is TRANSFORMED into circle so the perimeter of triangle will be equal to circumference of the circle,.

              circumference of circle  = Perimeter of triangle

               π d      =   26.4

         =    22/7 x d = 26.4

so we have Diameter (d) = 8.4 cm

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