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A piece of wire is bent in the shape of equilateral triangle each of whose sides measure 8.8 cm. This wire is rebent to form a circle. What is the diameter of the circle. |
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Answer» Answer: Diameter of circle will be - 8.4 cm Step-by-step explanation: Given SIDE of equilateral triangle = 8.8 cm So the perimeter of triangle will be 3 x 8.8 = 26.4 cm Now this triangle is TRANSFORMED into circle so the perimeter of triangle will be equal to circumference of the circle,. circumference of circle = Perimeter of triangle π d = 26.4 = 22/7 x d = 26.4 so we have Diameter (d) = 8.4 cm |
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