A piece of mass 40g is added to 200g of water at 50°c.calculate the final temperature of water when all the ice has melted.specific heat capacity ofwater=4200J/kg/K and specific latent heat of fusion of ice=336×10³J/kg.

A piece of mass 40g is added to 200g of water at 50°c.calculate the f

1.	A piece of mass 40g is added to 200g of water at 50°c.calculate the final temperature of water when all the ice has melted.specific heat capacity ofwater=4200J/kg/K and specific latent heat of fusion of ice=336×10³J/kg.
Answer» ⛦Hᴇʀᴇ Is Yoᴜʀ Aɴsᴡᴇʀ⚑ ▬▬▬▬▬▬▬▬▬▬▬▬☟ Let t be the final TEMPERATURE. ➧ Then HEAT Liberated by water ➾ m X c x Δt ➾ [200 x 10-3 x 4.2 x 103 x (50 – t)] ➾ (42,000 – 840t) ➧ Heat absorbed by ice to change into water at 0oC ➾ 40 x 10 x 336 x 103 ➾ 13,440 J. ➧ Heat absorbed by water to change its temperature from 0oC to toC ➾ (40 x 10-3 x 4.2x 103 x t) ➾ 168t ➧ Total heat absorbed by water ➾ (13,440 + 168t) J ➧ According to the principle of calorimetry, ➧ Heat given = Heat taken ♦ 42000 – 840t ➾ 13440 + 168t ♦ 42000 – 13440 ➾ 168t + 840t ♦ 1008t = 28560 t = 28560 / 1008 ➾ 28.33oC ...✔ __________ Thanks...✊

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A piece of mass 40g is added to 200g of water at 50°c.calculate the final temperature of water when all the ice has melted.specific heat capacity ofwater=4200J/kg/K and specific latent heat of fusion of ice=336×10³J/kg.

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