A piece of ice of mass 0.04 kg is added to 0.2 kg of water at 50 °C. Calculate final temperature of water when all ice has melted.Sp. Heat capacity of water =4200 J/kg°CSp. Latent heat of fusion of ice =336*10^3 J/kg.

A piece of ice of mass 0.04 kg is added to 0.2 kg of water at 50 °C.

1.	A piece of ice of mass 0.04 kg is added to 0.2 kg of water at 50 °C. Calculate final temperature of water when all ice has melted.Sp. Heat capacity of water =4200 J/kg°CSp. Latent heat of fusion of ice =336*10^3 J/kg.
Answer» ⛦Hᴇʀᴇ Is Yoᴜʀ Aɴsᴡᴇʀ⚑ ▬▬▬▬▬▬▬▬▬▬▬▬☟ Let t be the final temperature. ➧ Then heat LIBERATED by water ➾ m X c x Δt ➾ [200 x 10-3 x 4.2 x 103 x (50 – t)] ➾ (42,000 – 840t) ➧ Heat absorbed by ice to change into water at 0oC ➾ 40 x 10 x 336 x 103 ➾ 13,440 J. ➧ Heat absorbed by water to change its temperature from 0oC to toC ➾ (40 x 10-3 x 4.2x 103 x t) ➾ 168t ➧ Total heat absorbed by water ➾ (13,440 + 168t) J ➧ According to the principle of calorimetry, ➧ Heat GIVEN = Heat taken ♦ 42000 – 840t ➾ 13440 + 168t ♦ 42000 – 13440 ➾ 168t + 840t ♦ 1008t = 28560 t = 28560 / 1008 ➾ 28.33oC ...✔ __________ Thanks...✊

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A piece of ice of mass 0.04 kg is added to 0.2 kg of water at 50 °C. Calculate final temperature of water when all ice has melted.Sp. Heat capacity of water =4200 J/kg°CSp. Latent heat of fusion of ice =336*10^3 J/kg.

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