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A piece of ice having a stone frozen in it floats in a glass vessel filled with water. How will the level of water in the vessel change when the ice melts? |
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Answer» Correct Answer - A::C::D Let,` m_(1)=`mass of ice,` m_(2)=`mass of stone `rho_(s)=`density of stone and `rho_(w)=` density of water In equilibrium, when the piece of ice floats in water, weight of (ice+stone)=upthrust or, `(m_(1)+m_(2))=V_(i)rho_(w)g` `:. V_(i)=(m_(1))/(rho_(w))+(m_(2))/(rho_(w))` ...(i) Here, `V_(i)=` Volume of ice immersed When the ice melts, `m_(1)` mass of ice converts into water and stone of mass`m_(2)` is completely submerged. Volume of water formed by `m_(1)` mass of ice, `V_(1)=(m_(1))/(rho_(w))` Volume of stone (which is also equal to the volume of water displaced) `V_(2)=(m_(2))/(rho_(s))` Since, `rho_(s)gtrho_(w)` therefore, `V_(1)+V_(2)ltV_(1)` or the level of water will decrease. |
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