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A piece of gold weighs 10g in air and 9g in water. What is the volume of cavity? (Density of gold =`19.3 g cm^(-3)`)A. 0.282 ccB. 0.482 ccC. 0.682ccD. None of these |
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Answer» Correct Answer - B Actual volume of gold = `10//19.3 = 0.518 cm^(3)` Now, if `V` be the weight of gold in water = weight of `V` volume of water `implies 10-9 = V xx 1 = 1 c c` Volume of cavity = `1-0.518 = 0.482 C C`. |
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