A physical quantity P is given by p= [A^3.B^2/3]/(C^4.D^1/2) where A,B,C,D are 1%,3%,1%,2% , the relative percentage error is what?

A physical quantity P is given by p= [A^3.B^2/3]/(C^4.D^1/2) where A,B

1.	A physical quantity P is given by p= [A^3.B^2/3]/(C^4.D^1/2) where A,B,C,D are 1%,3%,1%,2% , the relative percentage error is what?
Answer» RELATIVE ERROR = HOPE you find it helpful.❤️Please mark as BRAINLIEST

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A physical quantity P is given by p= [A^3.B^2/3]/(C^4.D^1/2) where A,B,C,D are 1%,3%,1%,2% , the relative percentage error is what?

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