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A physical quantity P is given by p= [A^3.B^2/3]/(C^4.D^1/2) where A,B,C,D are 1%,3%,1%,2% , the relative percentage error is |
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Answer» As P=(a^3b^2)/(c^4d^1/2)a^3 b^2 c^4 d^1/2ΔP= 3Δa/a + 2Δb/b + 4Δc/c + 1/2Δd/dΔa/a=1% Δb/b=3% Δc/c=1% Δd/d=2%ΔP=(3X1) + (2X3) + (4x1) + (1/2x2)ΔP= 3 + 6 + 4 + 1ΔP=14% |
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