1.

A person walks up a stationary escalator in time t_(1). If the remains stationary on the escalator, then it can take him up in time t_(2). How much time would it take him to walk up the moving escalator ?

Answer»

Solution :Let L be the LENGTH of ESCALATOR.
Speed of MAN w.r.t. escalator is `v_("me") = (L)/(t_(1))`.
Speed of escalator `v_(E) = (L)/(t_(2))`.
Speed of man with respect to ground would be
`v_(m) = v_("me") + v_(e) = L((1)/(t_(1)) + (1)/(t_(2)))`
`therefore` The desired TIME is `t = (L)/(v_(m)) = (t_(1)t_(2))/(t_(1) + t_(2))`


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