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A person walks up a stationary escalator in time t_(1). If the remains stationary on the escalator, then it can take him up in time t_(2). How much time would it take him to walk up the moving escalator ? |
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Answer» Solution :Let L be the LENGTH of ESCALATOR. Speed of MAN w.r.t. escalator is `v_("me") = (L)/(t_(1))`. Speed of escalator `v_(E) = (L)/(t_(2))`. Speed of man with respect to ground would be `v_(m) = v_("me") + v_(e) = L((1)/(t_(1)) + (1)/(t_(2)))` `therefore` The desired TIME is `t = (L)/(v_(m)) = (t_(1)t_(2))/(t_(1) + t_(2))` |
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