1.

A person travelling a 432 km/h applies the brake giving a deceleration of 6.0 scooter. How far will it travel before stopping?4) 10m312m​

Answer»

initial velocity (u) = 432 km/hconvert it to m/s , multiply it by 5/18432(5/18) = 120 m / sas BRAKES are APPLIED , hence final velocity (v) = 0 m/sdeceleration provided = - 6.0 m / s^2 now , by formula v^2 - u ^2 = 2as putting values --(0)^2 - (120)^2 = 2(-6)s 14400 = - 12 s s = - 14400 / 12 ( neglecting negative sign)s = 1200 m



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