A person throws balls into air vertically upward in regular intervals of time of one second . The next ball is thrown when the velocity of the ball thrown earlier becomes zero . The height to which the balls rise is … (Assume , g = 10 ms^(-2))

A person throws balls into air vertically upward in regular intervals

1.	A person throws balls into air vertically upward in regular intervals of time of one second . The next ball is thrown when the velocity of the ball thrown earlier becomes zero . The height to which the balls rise is … (Assume , g = 10 ms^(-2))
Answer» 5 m 10 m 7.5m 20m Solution :Sice the ball are THROWN after a gap of 1S. So 1s is TIME of ascent of first ball. `:.` time of descent is also 1s `:. H=(1)/(2)G t^(2)` `=(1)/(2)xx10xx1^(2)=5m`

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A person throws balls into air vertically upward in regular intervals of time of one second . The next ball is thrown when the velocity of the ball thrown earlier becomes zero . The height to which the balls rise is … (Assume , g = 10 ms^(-2))

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