1.

A person starts from point X at 6:00 am. He reaches point Y and Z at 7:00 am and 9:00 am respectively. When he takes 2 hours to return to point X and the distance XY and YZ is 30 km and 60 km respectively, calculate the average speed of the person

Answer»

at the first TRIP he took 3 HRS to travel 90 km and at the second trip he took 2 hrs to travel 90 km then average speed is (speed of first trip + speed of second trip) /2therefore ANS is 37.5 kmph



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