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A person standing between two vertical cliffs and 480m from the nearest cliff [3] shouts. He hears the first echo after 3s and the second echo 5s later. Calculate : the speed of sound and the distance of the outer cliff from the person. |
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Answer» Total distance travelled by the sound in going and COMING back (in the case of the nearest cliff) =2×480 m Speed of sound = Timetaken Totaldistancetravelled
= 3 2×480
=320m/s ii)Time taken to reach second echo=3+2=5 s Now v= t 2d
⇒ d= 2 vt
Distance of the other cliff from the PERSON = 2 320×5
=800m. HOPE it will help you PLEASE mark me brainleist and follow me |
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